(1/2)x^2-10x+4=0

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Solution for (1/2)x^2-10x+4=0 equation: 


x in (-oo:+oo)

(1/2)*x^2-(10*x)+4 = 0

(1/2)*x^2-10*x+4 = 0

1/2*x^2-10*x+4 = 0

DELTA = (-10)^2-(1/2*4*4)

DELTA = 92

DELTA > 0

x = (92^(1/2)+10)/(1/2*2) or x = (10-92^(1/2))/(1/2*2)

x = 2*23^(1/2)+10 or x = 10-2*23^(1/2)

x in { 10-2*23^(1/2), 2*23^(1/2)+10 }

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